a mixture is made up of 3.35g of SiO2, 0.38g of cellulose and 8.76g of calcium carbonate. What is the percent of cellulose in the sample?

Solution:

mass of the cellulose in the mixture is 0.38g

total mass of the mixture is:

3.35+0.38+8.76

=12.4g

thus the percentage of the cellulose in the mixture is:

mass of the cellulose/total mass of the mixture*100%

0.38/12.4*100%

=3%