A gas under an initial pressure of 0.60 atm is compressed at constant temperature from 27 L to 3.0 L. The final presstre

becomes

Answer: 0.067atm

Explanation:

The relationship between the pressure and the volume of a gas at constant temperature is explained by Boyle's law.

According to Boyle's law

P1/V1 = P2 / V2

Initial pressure P1 = 0.60 atm

Final pressure P2 = ?

Initial Volume V1 = 27liters

Final volume V2 = 3.0L

Thus, 0.6/27 = P2/3.0

cross multiply

3.0 x 0.6 = P2 x 27

1.8 = 27P2

To get P2, divide both sides by 27

1.8/27 = 27P2/27

0.067atm = P2

Thus, the final pressure of the gas becomes 0.067atm