A balloon contains 0.950 mol of nitrogen gas and has a volume of 25.5 L. How many grams of N2 should be released from the balloon to bring the volume to 17.3 L

Mass released = 8.6 g

Explanation:

Given dа ta:

Initial number of moles nitrogen = 0.950 mol

Initial volume = 25.5 L

Final mass of nitrogen released = ?

Final volume = 17.3 L

Solution:

Formula:

V₁/n₁ = V₂/n₂

25.5 L / 0.950 mol = 17.3 L/n₂

n₂ = 17.3 L * 0.950 mol/25.5 L

n₂ = 16.435 L. mol / 25.5 L

n₂ = 0.644 mol

Initial mass of nitrogen:

Mass = number of moles * molar mass

Mass = 0.950 mol * 28 g/mol

Mass = 26.6 g

Final mass of nitrogen:

Mass = number of moles * molar mass

Mass = 0.644 mol * 28 g/mol

Mass = 18.0 g

Mass released = initial mass - final mass

Mass released = 26.6 g - 18.0 g

Mass released = 8.6 g