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5 October, 23:41

What is the empirical formula for a substance that contains 3.730% hydrogen, 44.44% carbon, and 51.83% nitrogen by mass?/?

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  1. 6 October, 00:29
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    Given dа ta:

    Hydrogen (H) = 3.730 % by mass

    Carbon (C) = 44.44%

    Nitrogen (N) = 51.83 %

    This means that if the sample weighs 100 g then:

    Mass of H = 3.730 g

    Mass of C = 44.44 g

    Mass of N = 51.83 g

    Now, calculate the # moles of each element:

    # moles of H = 3.730 g / 1 g. mole-1 = 3.730 moles

    # moles of C = 44.44/12 = 3.703 moles

    # moles of N = 51.83/14 = 3.702 moles

    Divide by the lowest # moles:

    H = 3.730/3.702 = 1

    C = 3.703/3.702 = 1

    N = 3.702/3.702 = 1

    Empirical Formula = HCN
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