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16 May, 09:00

What mass of Ba3 (PO4) 2 is contained in 1575 mL of a 0.35M solution of Ba3 (PO4) 2

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  1. 16 May, 10:05
    0
    = 331.81 g

    Explanation:

    Molarity is calculated by the formula;

    Molarity = Moles/volume in liters

    Therefore;

    Moles = Molarity * Volume in liters

    = 0.35 M * 1.575 L

    = 0.55125 Moles

    But; Molar mass of Ba3 (PO4) 2 is 601.93 g/mol

    Thus;

    Mass = 0.55125 moles * 601.93 g/mol

    =331.81 g
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