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14 March, 18:37

How much heat is added if 0.2067g of water is increased in temperature by 0.855

degrees C?

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Answers (1)
  1. 14 March, 19:45
    0
    0.756 J

    Explanation:

    Temperature change (delta T) = 0.855 degrees Celsius

    Mass of water (m) = 0.2067 g

    Specific heat capacity of water (c) = 4.28 J/g degrees C

    Heat added = m * c * delta T

    = (0.2067 * 4.28 * 0.855) J

    = 0.756 J
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