How many moles of NaCl are in 1.25 L of a 0.330 M NaCl solution?

Answer: 0.4 moles

Explanation:

Given that,

Amount of moles of NaCl (n) = ?

Volume of Nacl solution (v) = 1.25 L

Concentration of NaCl solution (c) = 0.330 M

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

Make n the subject formula

n = c x v

n = 0.330 M x 1.25 L

n = 0.4125 moles (To 2 significant figures, n becomes 0.4 moles)

Thus, 0.4 moles of NaCl are in 1.25 L of a 0.330 M NaCl solution