What is the pressure of 0.500mol of gas at 12.2 L and 273K

P = 0.92 atm

Explanation:

Given dа ta:

Pressure of gas = ?

Number of moles = 0.500 mol

Volume of gas = 12.2 L

Temperature of gas = 273 K

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P = Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm. L / mol. K

T = temperature in kelvin

Now we will put the values.

P = nRT/v

P = 0.500 mol * 0.0821 atm. L / mol. K * 273 K / 12.2 L

P = 11.2 / 12.2 L

P = 0.92 atm