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31 December, 16:34

Estimate the ph of the resulting solution prepared by mixing 1.0 mole of solid disodium phosphate (na2hpo4) and 1.25 mole of hydrochloric acid. The pka values for phosphoric acid are 2.1, 7.2 and 12.4.

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  1. 31 December, 16:54
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    The HCl added = 1.25 moles

    and the moles of Na2HPO4 = 1 mole

    Now when acid is added in the given solution of Na2HPO4

    One mole of H + will react with one mole of Na2HPO4 to given one mole of NaH2PO4

    Na2HPO4 + H + - --> NaH2PO4

    Now this one mole formed NaH2PO4 will further react with 0.25 moles of H + left to form 0.25 moles of H3PO4 and 0.75 moles of NaH2PO4 will remain in the solution

    So this will result into formation of a buffer of phosphoric acid and NaH2PO4

    NaH2PO4 + H + - --> H3PO4

    pKa of H3PO4 = 2.1

    so pH = pKa + log [salt] / [acid] = 2.1 + log [0.75 / 0.25] = 2.58

    so the pH will be in between 2.1 to 7.2
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