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14 June, 04:43

A chemist dissolves 660. mg of pure hydroiodic acid in enough water to make up 300. mL of solution. Calculate the pH of the solution. Round your answer to 3 significant decimal places.

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  1. 14 June, 07:45
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    660mg = 0.660g

    300mL = 0.300L

    0.660g/0.300L = 2.2M

    ICE Box

    HI + H2O - -> H3O + I-

    I. 2.2M 0M 0M

    C - x + x + x

    E 2.2M x x

    You would need k to find x using the equation k = [H3O][I-]/[HI]. To find the pH, use the equation pH = - log[H3O].
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