Acetic acid (CH3COOH) has a heat of vaporization of 23.4 kJ/mol. What heat is required to vaporize 250 g of acetic acid?

97.5 kJ of heat is required to vaporize 250 g of acetic acid

Explanation:

Acetic acid → CH₃COOH

The heat of vaporization is 23.4 kJ/mol, which it means that 1 mol of acetic releases 23.4 kJ of energy.

Let's convert our mass of acetic to moles:

250 g. 1 mol / 60 g = 4.17 moles

Now we propose this rule of three:

1 mol of acetic acid releases 23.4 kJ

Then, 4.17 moles will release (4.17. 23.4) / 1 = 97.5 kJ