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31 July, 12:02

What is the concentration of a solution of a 40.0 g of NaOH in 2.5 L of solution?

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  1. 31 July, 14:06
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    Answer: 0.4M

    Explanation:

    Given that,

    Amount of moles of NaOH (n) = ?

    Mass of NaOH in grams = 40.0g

    For molar mass of NaOH, use the atomic masses: Na = 23g; O = 16g; H = 1g

    NaOH = (23g + 16g + 1g)

    = 40g/mol

    Since, n = mass in grams / molar mass

    n = 40.0g / 40.0g/mol

    n = 1 mole

    Volume of NaOH solution (v) = 2.5 L

    Concentration of NaOH solution (c) = ?

    Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

    c = n / v

    c = 1 mole / 2.5 L

    c = 0.4 mol/L (Concentration in mol/L is the same as Molarity, M)

    Thus, the concentration of a solution of a 40.0 g of NaOH in 2.5 L of solution is 0.4 mol/L or 0.4M
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