How many milliliters of a 0.80 M sucrose solution contain each of the following number of grams? The molar mass of sucrose (C12H22O11) is 342.3 g/mol.

a. 7.45 g

b. 17.0 mg

The number of Ml of 0.80 M sucrose solution that contain

(A) 7.45 g are 27.25 Ml

calculation

volume = moles / molarity

molarity = 0.80 M which is the same as 0.80 mol/l

moles = mass/molar mass

= 7.45 g / 342.3 g/mol = 0.0218 moles

volume is therefore = 0.0218 moles / 0.80 mol/L=0.02725 L

convert into ml by multiplying by 1000

= 27.25 ml

question b

volume = moles/molarity

molarity = 0.80 M = 0.80 Mol/L

moles = mass/molar mass

mass 17.0 mg convert into g by diving by 1000=0.017 g

moles is therefore = 0.017 g / 342.3 g/mol = 4.97 x10^-5 moles

volume = (4.97 x 10^-5 moles) / 0.8 mol / l=6.21 x10^-5 L

= 6.21 x10^-5 x 1000 = 0.0621 Ml