Air in a closed cylinder is heated from 25 degree C to 36 degree C. If the initial pressure is 3.80 atm what is the final pressure

Answer: 3.94 atm

Explanation:

Given that,

Initial pressure (P1) = 3.80atm

Initial temperature (T1) = 25°C

since the standard unit of temperature is Kelvin, convert 25°C to Kelvin

(25°C + 273 = 298K)

Final pressure P2 = ?

Final temperature T2 = 36°C

(36°C + 273 = 309K)

Since pressure and temperature are given while volume is held constant, apply the formula for Pressure's law

P1/T1 = P2/T2

3.80 atm / 298K = P2 / 309K

To get the value of P2, cross multiply

3.80 atm x 309K = P2 x 298K

1174.2 atm•K = 298K•P2

Divide both sides by 298K

1174.2 atm•K/298K = 298K•P2/298K

3.94 atm = P2

Thus, the final pressure is 3.94 atm

the final pressure is 3.94 atm

Explanation:

Given that,

Initial pressure (P1) = 3.80atm

Initial temperature (T1) = 25°C

since the standard unit of temperature is Kelvin, convert 25°C to Kelvin

(25°C + 273 = 298K)

Final pressure P2 = ?

Final temperature T2 = 36°C

(36°C + 273 = 309K)

Since pressure and temperature are given while volume is held constant, apply the formula for Pressure's law

P1/T1 = P2/T2

3.80 atm / 298K = P2 / 309K

To get the value of P2, cross multiply

3.80 atm x 309K = P2 x 298K

1174.2 atm•K = 298K•P2

Divide both sides by 298K

1174.2 atm•K/298K = 298K•P2/298K

3.94 atm = P2

Thus, the final pressure is 3.94 atm