Ask Question
11 March, 16:35

Consider the reaction.

Pb (SO4) 2 + 2 Zn → 2 ZnSO4 + Pb

If 0.311 mol of zinc reacts with excess lead (IV) sulfate, how many grams of zinc sulfate will be produced in the reaction?

+4
Answers (2)
  1. 11 March, 20:11
    0
    mass ZnSO₄ = 50.2 gms (3 sig. figs.)

    Explanation:

    Pb (SO₄) ₂ (aq) + 2 Zn (s) = > ZnSO₄ (aq) + Pb (s)

    => Because coefficients of Zn and ZnSO₄ are the same, 0.311 mole Zn (s) yields the same 0.311 mol ZnSO₄ (aq).

    => Convert moles to grams by multiplying 0.311 moles ZnSO₄ by formula weight of ZnSO₄ ( = 161.4 g/mol)

    That is, grams ZnSO₄ = 0.311 mole ZnSO₄ x 161.4 g/mol = 50.1954 g ≅ 50.2 g (3 sig. figs.)
  2. 11 March, 20:17
    0
    Answer: m = 50 g ZnSO4

    Explanation: First is convert the moles of Zn to the moles of ZnSO4 by having their mole ratio which is 2:2 based from the balanced equation. Next is convert the moles of ZnSO4 to mass using its molar mass.

    0.311 mole Zn x 2 moles ZnSO4 / 2 moles Zn

    = 0.311 moles ZnSO4

    0.311 moles ZnSO4 x 161 g ZnSO4 / 1 mole ZnSO4

    = 50 ZnSO4
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Consider the reaction. Pb (SO4) 2 + 2 Zn → 2 ZnSO4 + Pb If 0.311 mol of zinc reacts with excess lead (IV) sulfate, how many grams of zinc ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers