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8 January, 05:02

0.25 mol of nitric acid is used to make a 0.10 M nitric acid solution. How many grams of solute was used?

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  1. 8 January, 08:01
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    15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution

    Explanation:

    Step 1: Data given

    Nitric acid = HNO3

    Molar mass of H = 1.01 g/mol

    Molar mass of N = 14.0 g/mol

    Molar mass O = 16.0 g/mol

    Number of moles nitric acid (HNO3) = 0.25 moles

    Molairty = 0.10 M

    Step 2: Calculate molar mass of nitric acid

    Molar mass HNO3 = Molar mass H + molar mass N + molar mass (3*O)

    Molar mass HNO3 = 1.01 + 14.0 + 3*16.0

    Molar mass HNO3 = 63.01 g/mol

    Step 3: Calculate mass of solute use

    Mass HNO3 = moles HNO3 * molar mass HNO3

    Mass HNO3 = 0.25 moles * 63.01 g/mol

    Mass HNO3 = 15.75 grams

    15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution
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