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11 April, 19:46

Solve this problem using the appropriate law. (Remember that) What is the pressure of 1.9 mols of nitrogen gas in a 9.45 L tank and at a temperature of 228 K?

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Answers (2)
  1. 11 April, 21:28
    0
    P = 3.7635 atm

    Explanation:

    We can use any law that involves pressure. However, as we are talking here of a gas, we better use the ideal gas equation, which is shorter and easier to use.

    The ideal gas equation is:

    PV = nRT

    And solving for P:

    P = nRT/V

    Where:

    P: Pressure in atm

    n: moles of the gas

    R: gas constant which is 0.0821 L atm / mol K

    V: Volume of the gas or container

    T: Temperature of the reaction or container.

    In this case, we have all the data, so we just replace the given data in the above expression to calculate pressure:

    P = 1.9 * 0.0821 * 228 / 9.45

    P = 35.56572 / 9.45

    P = 3.7635 atm

    This is the pressure of nitrogen gas.
  2. 11 April, 23:45
    0
    PV=nRT

    You are funding pressure and you have V = 9.45L, n = 1.9 moles, R = gas constant, and T = 228 K

    P (9.45L) = (1.9moles) (0.0821) (228K)

    Find P

    Multiply

    9.45P = 35.57

    Divide

    P = 3.76 L of N

    Answer should be 3.76 liters of nitrogen
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