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23 October, 23:31

Gases [9A. R, 9B. S]:Question 10

What volume does 3.0 mol of a gas occupy at 2 atm and 10 °C

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Answers (1)
  1. 24 October, 02:48
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    The volume is 35L

    Explanation:

    We use the formula PV=nRT. We convert the temperature in Celsius into Kelvin: 0°C=273K---> 10°C=273+10 = 283K

    PV=nRT - --> V = (nRT) / P

    V = (3 mol x 0,082 l atm/K mol x 283K) / 2 atm

    V=34, 809 L
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