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31 August, 02:31

what is the percentage yield of carbon disulfide if the reaction of 32.0g of sulfur dioxide produces 12.0g of carbon disulfide?

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  1. 31 August, 04:08
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    Answer;

    = 63.04 %

    Explanation;

    The balanced equation for the reaction;

    5 C + 2 SO2 → CS2 + 4 CO

    We can calculate the theoretical yield;

    = (32.0 g SO2) / (64 g C/mol) x (1/2) x (76.1418 g CS2/mol)

    = 19.035 g CS2 in theory

    But;

    Percentage yield = Actual yield/theoretical yield * 100%

    = (12.0 g) / (19.035 g) * 100%

    = 0.6304 * 100%

    = 63.04%
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