How many grams of glucose would be present in one liter of a 1 m solution of glucose?

Mass = 180 g

Solution:

Step 1: Calculate Moles using following Formula,

Molarity = Moles : Volume

Solving for Moles,

Mole = Molarity * Volume

Putting values,

Mole = 1 mol. L⁻¹ * 1 L

Mole = 1 moles

Step 2: Calculate mass using following formula,

Moles = Mass : M. Mass

Solving for Mass,

Mass = Moles * M. Mass

Putting Values,

Mass = 1 mol * 180 g. mol⁻¹

Mass = 180 g