A flexible container is filled with 960.0 liters of air at 38 degrees Celsius. If pressure in the container does not change, at what temperature will the container have at a volume of 350.0 liters?

- 159.6°C

Explanation:

Data obtained from the question include:

V1 (initial volume) = 960L

T1 (initial temperature) = 38°C = 38 + 273 = 311K

V2 (final volume) = 350L

T2 (final temperature) = ?

Since the pressure is constant, then Charles' law is in operation. Using the Charles' law equation V1/T1 = V2/T2, we can easily obtain the final temperature as follow:

V1/T1 = V2/T2

960/311 = 350/T2

Cross multiply to express in linear form.

960 x T2 = 311 x 350

Divide both side by 960

T2 = (311 x 350) / 960

T2 = 113.4K

Now let us convert 113.4K to a number in celsius scale. This is illustrated below:

°C = K - 273

°C = 113.4 - 273

°C = - 159.6°C

Therefore, the container will have a volume of 350L at - 159.6°C