A 1.2 L weather balloon on the

ground has a temperature of 25°C

and is at atmospheric pressure (1.0

atm). When it rises to an elevation

where the pressure is 0.74 atm,

then the new volume is 1.8 L. What

is the temperature (in °C) of the air

at this elevation?

Question

Chemistry

Danny Adams

6 November, 19:51

A 1.2 L weather balloon on the

ground has a temperature of 25°C

and is at atmospheric pressure (1.0

atm). When it rises to an elevation

where the pressure is 0.74 atm,

then the new volume is 1.8 L. What

is the temperature (in °C) of the air

at this elevation?

+4

Answers (1)

Know the Answer?

Dayanara Lynn · Answer 1

330.95K

Explanation:

V₁ = 1.2L

T₁ = 25°C = (25 + 273.15) K = 298.15K

P₁ = 1.0 atm

P₂ = 0.74 atm

V₂ = 1.8L

T₂ = ?

From combined gas equation,

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Solve for T₂

T₂ = (P₂ * V₂ * T₁) / (P₁ * V₁)

T₂ = (0.74 * 1.8 * 298.15) / (1.0 * 1.2)

T₂ = 397.1358 / 1.2

T₂ = 330.9465K

T₂ = 330.95K or T₂ = (330.95 - 273.15) °C = 57.8°C

A 1.2 L weather balloon on theground has a temperature of 25°Cand is at atmospheric pressure (1.0atm). When it rises to an elevationwhere the pressure is 0.74 atm,then the new volume is 1.8 L. Whatis the temperature (in °C) of the airat this elevation?

A 1.2 L weather balloon on the

ground has a temperature of 25°C

and is at atmospheric pressure (1.0

atm). When it rises to an elevation

where the pressure is 0.74 atm,

then the new volume is 1.8 L. What

is the temperature (in °C) of the air

at this elevation?