Find the mass, in grams, of 5.00*10^23 molecules of F2

Answer: 31.55 g

Explanation:

- The mass number of Fluoride atom (F) = 18.99 g/mol, so mass number of fluorine gas (F2) = 37.98 g/mol.

- 1 mole of (F2) [which has 37.98 g/mol] contains Avogadro's number of molecules (6.02*10^23 molecules),

so 1 mole of (F2) with 37.98 g/mol → 6.02*10^23 molecules.

- Using cross multiplication,

37.98 g/mol of (F2) → 6.02 * 10^23 molecules

? → 5.00 * 10^23 molecules

Hence the mass of 5.00*10^23 molecules of F2 = (37.98 * 5.00 * 10^23) / 6.02 * 10^23 = 31.55 g ...