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23 December, 20:00

Calculate the poH of a substance with [OH-] of 3.0 x 10^-6 M.

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Answers (2)
  1. 23 December, 20:39
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    pOH = 5.52

    Explanation:

    pOH = - log[OH] = - log[3.0 x 10^-6]

    pOH = 5.52
  2. 23 December, 23:03
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    Hello how are you doing
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