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8 February, 01:05

Calculate the ph of a solution containing 0.75 m lactic acid and 0.25 m sodium lactate. recalculate after the addition of 0.05ml of hcl

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  1. 8 February, 03:46
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    pH = pKa+log[A-]/[HA]

    pKa=-log (Ka)

    -log (1.4/10^-4) (the Ka of lactic acid)

    pKa=3.85

    pH=3.85+log (0.25/.75)

    pH=3.37

    HCl is an acid, so the 0.05M HCl is added to the acid and subtracted from the base

    pH = 3.85 + log (0.24/0.76)

    pH=3.35 after addition of HCl
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