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14 January, 14:07

A compound has a molar mass of 92.02 grams/mole, and its percent composition is 30.4% nitrogen (N) and 69.6% oxygen (O). What is its molecular formula? A. N2O4 B. NO2 C. N2O D. N4O2

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  1. M
    14 January, 17:07
    0
    The answer is: A. N2O4.

    M (NₓOₙ) = 92.02 g/mol; molar mass of unknown compound.

    If we take 100 grams of sample:

    m (N) = 0.304 · 100 g.

    m (N) = 30.4 g; mass of nitrogen.

    n (N) = 30.4 g : 14.01 g/mol.

    n (N) = 2.17 mol; amount of nitrogen.

    m (O) = 0.696 · 100 g.

    m (O) = 69.6 g; mass of oxygen

    n (O) = 69.6 g : 16 g/mol.

    n (O) = 4.35 mol; amount of oxygen.

    n (N) : n (O) = 2.17 mol : 4.35 mol.

    n (N) : n (O) = 1 : 2.

    Answer is N₂O₄ or NO₂, so we must find molar mass.

    M (N₂O₄) = 2Ar (N) + 4Ar (O) · g/mol.

    M (N₂O₄) = 92.02 g/mol.
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