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23 February, 22:53

The reaction 2HGOS (S) - 2Hg (1) + 02 (g), you produce 1 mole of HG. What is your percent yield? you expected to produce 2mol of HG.

100%

50%

30%

20%

+4
Answers (1)
  1. 24 February, 00:46
    0
    Option 2. 50 %

    Explanation:

    Reaction: 2HgO (s) → 2Hg (l) + O₂ (g)

    Ratio is 2:2, 2 moles of mercury oxide produce 2 moles of liquid mercury.

    If you produced 1 mol of Hg, then the percent yield reaction is 50%

    Percent yield is:

    [Produced yield (what you produced) / Theoretical yield (what you excpected to be produced) ]. 100 → (1 mol of Hg / 2 mol of Hg).100 = 50%
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