If a certain mass of mercury has a volume of 0.002 m2 at a temperature of 20 celsius, what will be the volume of 50 celsius?

Answer: 0.0022m3

Explanation:

Initial volume of mercury V1 = 0.002m3 (note that the unit of volume can be cm3, m3, dm3 or liters)

Initial temperature T1 = 20°C

Convert temperature in Celsius to Kelvin

(20°C + 273°C = 293K)

Final temperature T2 = 50°C

(50°C + 273°C = 323K)

Final volume V2 = ?

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

0.002/293 = V2/323

To get the value of V2, cross multiply

V2 = (323 x 0.002) / 293

V2 = 0.646 / 293

V2 = 0.0022 m3

Thus, the new volume of mercury will be 0.0022m3