Ask Question
1 September, 14:03

Which equation represents the total ionic equation for the reaction of HNO3 and NaOH? Upper H superscript plus, plus upper O upper H superscript minus right arrow upper H subscript 2 upper O. Upper H upper N upper O subscript 3 plus upper N a upper O upper H right arrow upper N a upper N upper O subscript 3 plus upper H subscript 2 upper O. Upper H superscript plus, plus upper N upper O subscript 3 superscript minus plus upper N a superscript plus, plus upper O upper H superscript minus right arrow upper N a superscript plus, plus upper N upper O subscript 3 superscript minus, plus upper H subscript 2 upper O. Upper H superscript plus, plus upper N upper O subscript 3 superscript minus, plus upper O upper H superscript minus right arrow upper N upper O subscript 3 superscript minus, plus upper H subscript 2 upper O.

+2
Answers (2)
  1. 1 September, 15:46
    0
    Its C on edge2020
  2. 1 September, 17:26
    0
    Total Ionic equation:

    H⁺ (aq) + NO₃⁻ (aq) + Na⁺ (aq) + OH⁻ (aq) → H₂O (l) + Na⁺ (aq) + NO₃⁻ (aq)

    Explanation:

    Chemical equation:

    HNO₃ + NaOH → NaNO₃ + H₂O

    Balanced chemical equation:

    HNO₃ (aq) + NaOH (aq) → NaNO₃ (aq) + H₂O (l)

    Total Ionic equation:

    H⁺ (aq) + NO₃⁻ (aq) + Na⁺ (aq) + OH⁻ (aq) → H₂O (l) + Na⁺ (aq) + NO₃⁻ (aq)

    Net ionic equation:

    H⁺ (aq) + OH⁻ (aq) → H₂O (l)

    The NO₃⁻ (aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

    Spectator ions:

    These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Which equation represents the total ionic equation for the reaction of HNO3 and NaOH? Upper H superscript plus, plus upper O upper H ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers