A rectangular block of lead (Pb) measures 20.0 mm X 30.0 mm X 45.0 mm. If the density of Pb is 11.34 g/cm3, calculate the mass of the block

Question

Chemistry

Ian Adams

30 April, 23:52

A rectangular block of lead (Pb) measures 20.0 mm X 30.0 mm X 45.0 mm. If the density of Pb is 11.34 g/cm3, calculate the mass of the block

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Answers (1)

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Morse · Answer 1

1. D=M / V

Convert mm to cm then multiply to get V.

V=20.0mm * 30.0mm * 45.0mm

V=2.00cm * 3.00cm * 4.50cm=27.0cm3

11.34g/cm3=M / 27.0cm3

M = 306g

2. A cube has the same dimensions for length, height, and width, therefore volume is 1.55cm*1.55cm*1.55cm=3.724cm3

D=M / V

D=71.9g / 3.724cm3

D=19.3g/cm3

3. Volume of the sample is 41.7mL-25.5mL=16.2mL or 16.2cm3 because 1mL=1cm3

D=M / V

D=43.6g / 16.2cm3

D=2.69g/cm3

4. D=M / V

D = 3175g / 2.00m*2.00m*5.00m

Convert m to cm and multiply to get volume

D=3175g / 2.00x10^7cm3

D=1.59x10^-4g/cm3 or 0.000159g/cm3

because 1cm3=1mL

D=1.59x10^-4g/mL or 0.000159g/mL

Since I do not have the table you need to reference, I have listed the volume in scientific notation and in decimal form for you to compare to your table.