A gas has a volume of 1.6 liters at STP. What is the new volume when the temperature is

changed to 60K and the pressure stays constant at 1.0 atm?

0.35L

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Initial volume (V1) = 1.6L

Initial pressure (P1) = stp = 1atm

Initial temperature (T1) = stp = 273K

Final temperature (T2) = 60K

Final pressure (P2) = constant (the same as initial pressure)

Final volume (V2) = ?

Step 2:

Determination of the new volume of the gas.

Considering the question given, the gas is obeying Charles' law since the pressure is constant. Thus, the final volume i. e the new volume of the gas can be obtained as follow:

V1/T1 = V2/T2

1.6/273 = V2/60

Cross multiply to express in linear form

273 x V2 = 1.6 x 60

Divide both side by 273

V2 = (1.6 x 60) / 273

V2 = 0.35L

Therefore, the new volume of the gas is 0.35L