How many joules of heat energy are required to raise the temperature of

100 grams of water from 21°C to 23°C?

836.8J

Explanation:

Heat energy = ?

Mass = 100g

Initial temperature (T1) = 21°C

Final temperature (T2) = 23°C

Specific heat capacity of water (c) = 4.184J/g°C

To solve this question, we'll need to use the formula for calculating heat energy of a substance.

Q = mc∇t

Q = heat energy of substance

M = mass of substance

C = specific heat capacity of substance

∇t = change in temperature = T2 - T1

Q = 100 * 4.184 * (23 - 21)

Q = 418.4 * 2

Q = 836.8J

The heat energy required to raise 100g of water from 21°C to 23°C is 836.8J