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19 March, 15:31

How many atoms of oxygen are contained in 160 grams of N2O3?

A. 1.27 * 1024

B. 1.81 * 1024

C. 3.80 * 1024

D. 6.28 * 1024

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Answers (2)
  1. 19 March, 15:40
    0
    3.80 * 1024 grams containing
  2. 19 March, 16:22
    0
    The number of oxygen atoms that are contained in 160 grams of N2O3 are 3.80 x10^24 atoms (answer C)

    Explanation

    Step 1: calculate the moles of N2O3

    moles = mass N2O3 / molar mass N2O3

    molar mass of N2O3 = (14 x2) + (16 x3) = 76 g/mol

    moles of N2O3 = 160 g / 76 g/mol = 2.105 moles

    Step 2: from the moles of N2O3 find the moles of Oxygen

    =moles of N2O3 x number of oxygen atoms in N2O3 (3)

    = 3 x 2.105 = 6.315 moles

    Step 3:use the Avogadro's law to calculate the atoms of oxygen

    that is according to Avogadro's law 1 mole = 6.02 x10 ^23 atoms

    6.315 moles=? atoms

    ={ (6.315 moles x 6.02 x10 ^23 atoms) / 1 mole} = 3.80 x10^24 atoms
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