What mass of Fe can be produced by the reaction of 75.0 g CO with excess Fe2O3 according to the equation: Fe2O3 (s) + CO (g) → Fe (s) + CO2 (g) ?

99.7 g Fe

Step-by-step explanation:

a) Write the balanced chemical equation

Fe2O3 + 3CO → 2Fe + 3CO2

b) Convert grams CO to moles CO

Moles CO = 75.0 g CO x (1 mol CO/28.01 g CO) = 2.678 mol CO

c) Use the molar ratio of Fe:CO to convert moles of CO to moles of Fe

2.678 mol CO x (2 mol Fe/3 mol CO) = 1.785 mol Fe

d) Convert moles of Fe to grams of Fe

1.785 mol Fe x (55.84 g Fe/1 mol Fe) = 99.7 g Fe