Determine the celsius temperature of 2.49 mol of gas contained in a 1.00 l vessel

Question

Chemistry

Karsyn Boyle

29 March, 00:51

Determine the celsius temperature of 2.49 mol of gas contained in a 1.00 l vessel

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Answers (1)

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Herman · Answer 1

= - 266.24°C

Explanation:

According to ideal gas law;

PV = nRT, where P is pressure, V is the volume, n is the number of moles, R is the ideal gas constant and T is the temperature.

PV = nRT

T = PV / (nR)

= 143 kPa * (1atm/101.325 kPa) * 1.00L / (2.49 mol * 0.08206 Latm/molK)

= 6.91 K

= - 266.24°C