What volume of 15.6M NH4OH is needed to make 500. mL of 3.00M solution?

V₁ = 96.2 mL

Explanation:

Given dа ta:

Initial volume of NH₄OH required = ?

Initial molarity = 15.6 M

Final molarity = 3.00 M

Final volume = 500.0 mL

Solution:

Formula:

M₁V₁ = M₂V₂

M₁ = Initial molarity

V₁ = Initial volume of NH₄OH

M₂ = Final molarity

V₂ = Final volume

Now we will put the values.

15.6 M * V₁ = 3.00 M*500.0 mL

15.6 M * V₁ = 1500 M. mL

V₁ = 1500 M. mL / 15.6 M

V₁ = 96.2 mL