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1 November, 10:53

What volume in liters will be occupied by 1.20 moles of helium gas at a pressure of 3.675 atm and 100*C?

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  1. 1 November, 12:54
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    V = 121.82 L

    Explanation:

    Given dа ta:

    Number of moles of gas = 1.20 mol

    Pressure of gas = 3.675 atm

    Temperature = 100°C

    Volume occupied = ?

    Solution:

    Formula:

    General gas equation:

    PV = nRT

    R = general gas constant.

    Now we will convert the temperature into kelvin.

    100+273 = 373 K

    V = nRT/P

    V = 1.2 mol * 0.0821 atm. L/mol. K * 373 K / 3.675 atm

    V = 447.68 / 3.675 atm

    V = 121.82 L
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