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19 August, 11:56

How many grams of NaC2H3O2 are needed to prepare 350. mL of a 2.75 M solution? (molar mass of

NaC2H3O2 = 82.04 g/mol)

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  1. 19 August, 14:04
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    78.96 g of NaC2H3O2

    Explanation:

    We are given;

    Volume of the solution as 350 mL Molarity of the solution as 2.75 M Molar mass of the solute NaC2H3O2 as 82.04 g/mol

    We are required to determine the mass of the solute;

    First we determine the number of moles;

    Moles = Molarity * Volume

    Therefore;

    Moles of the solute = 2.75 M * 0.350 L

    = 0.9625 moles

    Second, we determine the mass

    Mass = Moles * Molar mass

    = 0.9625 moles * 82.04 g/mol

    = 78.9635 g

    = 78.96 g

    Therefore, the mass of NaC2H3O2 needed is 78.96 g
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