An ideal gas sample with 7.20 atm pressure occupies 250mL voulme at 18•C. What volume would it occupy at 1.50atm and 216•C?

The volume of ideal gas that would occupy at 1.50 atm and 216 c is

2016.49 ml

calculation

volume is calculated using a combined gas equation

that is P1V1/T1 = P2V2/T2

P1 (pressure 1) = 7.20 atm

V1 (volume 1) = 250 ml

T1 (temperature 1) = 18 + 273=291 K

P2 (pressure 2) = 1.50 atm

T2 (temperature 2) = 216+273=489 K

V2 (volume 2) = ?

by making V2 the subject of the formula

V2=[ (T2 xP1 x V1) / (T1 xP2) ]

V2=[ (489 K x 7.20 atm x 250 ml) / (291 k x 1.50 atm) ] = 2016.49 Ml