Ask Question
20 May, 05:19

If 0.3041 g of a diprotic solid acid is neutralized by 35.45 ml of 0.0997 m naoh, calculate the malar mass of solid acid

+2
Answers (1)
  1. 20 May, 05:49
    0
    Number of moles required to neutralize the solution=0.0354*0.0997

    =0.0035mol

    2 mol of NaOH required to neutralize 1 mol of diprotic acid.

    So moles of acid 0.0035/2=0.0017

    Number of moles of acid=Mass of diprotic acid/Molar mass of diprotic acid

    0.0017 = 0.3041/Molar mass of diprotic acid

    Molar mass of diprotic acid=0.3041/0.0017

    =178.8 g/mol
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “If 0.3041 g of a diprotic solid acid is neutralized by 35.45 ml of 0.0997 m naoh, calculate the malar mass of solid acid ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers