If 38g of sodium hydroxide reacts with 28g of carbon, how many grams of sodium carbonate are produced?

Mass of sodium carbonate = 33.92 g

Explanation:

Given dа ta:

Mass of sodium hydroxide = 38 g

Mass of carbon = 28 g

Mass of sodium carbonate produced = ?

Solution:

Chemical equation:

6NaOH + 2C → 2Na + 3H₂ + 2Na₂CO₃

Now will calculate the number of moles of reactants:

Number of moles of sodium hydroxide:

Number of moles = mass / molar mass

Number of moles = 38 g / 40 g/mol

Number of moles = 0.95 mol

Number of moles of carbon:

Number of moles = mass / molar mass

Number of moles = 28 g / 16 g/mol

Number of moles = 1.75 mol

Now we will compare the moles of both reactant with sodium carbonate.

C : Na₂CO₃

2 : 2

1.75 : 1.75

NaOH : Na₂CO₃

6 : 2

0.95 : 2/6*0.95 = 0.32

Number of moles of sodium carbonate produced by sodium hydroxide are less so it will limiting reactant.

Mass of sodium carbonate:

Mass = number of moles * molar mass

Mass = 0.32 mol * 106 g/mol

Mass = 33.92 g