When 18.0 mL of a 8.43*10-4 M cobalt (II) fluoride solution is combined with 22.0 mL of a 9.72*10-4 M sodium hydroxide solution does a precipitate form? no (yes or no) For these conditions the Reaction Quotient, Q, is equal to.

Q = 1.08x10⁻¹⁰

Yes, precipitate is formed.

Explanation:

The reaction of CoF₂ with NaOH is:

CoF₂ (aq) + 2 NaOH (aq) ⇄ Co (OH) ₂ (s) + 2 NaF (aq).

The solubility product of the precipitate produced, Co (OH) ₂, is:

Co (OH) ₂ (s) ⇄ Co²⁺ (aq) + 2OH⁻ (aq)

And Ksp is:

Ksp = 3x10⁻¹⁶ = [Co²⁺][OH⁻]²

Molar concentration of both ions is:

[Co²⁺] = 0.018Lₓ (8.43x10⁻⁴mol / L) / (0.018 + 0.022) L = 3.79x10⁻⁴M

[OH⁻] = 0.022Lₓ (9.72x10⁻⁴mol / L) / (0.018 + 0.022) L = 5.35x10⁻⁴M

Reaction quotient under these concentrations is:

Q = [3.79x10⁻⁴M] [5.35x10⁻⁴M]²

Q = 1.08x10⁻¹⁰

As Q > Ksp, the equilibrium will shift to the left producing Co (OH) ₂ (s) the precipitate