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11 January, 13:06

The amide formed in the reaction of 3-ethylbenzoic acid and dimethylamine is

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  1. 11 January, 15:54
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    Answer: -

    3-Ethyl-N, N-dimethylbenzamide.

    Explanation: -

    In the first step the nitrogen lone pair attacks the carbonyl carbon.

    Then a OH becomes water molecule by protonation and leaves.

    Final step involves proton loss to form amide.
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