What is the molarity of a solution containing 45 grams of CaCl2 in 1.5 L of

water?

dа ta:

Mass of solute: 45 g

m. mass of solute: 110 g/mol

volume of water: 1.5 L

Explanation:

percent w/v: 45/1500 * 100

vol of solution: 3cm3=0.003dm3

M=g of solute/m. mass of solute*dm3 of sol

M = 45/110*0.003

M=14.85