A tank holding 7.80 L of gas is at a pressure of 9.80 atm. If the temperature and number of gas particles do not change, what is the new pressure at a volume of 5.3 L?

*Show Work*

A. 14.4 atm

B. 51.9 atm

C. 4.22 atm

D. 0.0693 atm

14.42 atm.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant.

T is the temperature of the gas in K.

If n and T are constant, and have two different values of V and P:

P₁V₁ = P₂V₂

P₁ = 9.8 atm, V₁ = 7.80 L.

P₂ = ? atm, V₂ = 5.30 L.

∴ P₂ = P₁V₁/V₂ = (9.8 atm) (7.80 L) / (5.30 L) = 14.42 atm.