At a certain temperature, the percent dissociation (ionization) of chlorous acid, HClO2, in a 1.43 M solution water is 8.0%. Calculate the value of Ka for chlorous acid at this temperature.

Kₐ = 9.9 * 10⁻³

Explanation:

HClO₂ + H₂O ⇌ H₃O⁺ + ClO₂⁻

0.080 * 1.43 = 0.1144

So, at equilibrium,

[H₃O⁺] = [ClO₂⁻] = 0.1144

[HClO₂] = 1.43 - 0.1144 = 1.316

Kₐ = {[H₃O⁺][ClO₂⁻]}/[HClO₂]; Substitute values

Kₐ = (0.1144 * 0.1144) / 1.316 Do the operations

Kₐ = 9.9 * 10⁻³