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10 February, 01:53

The volume of a gas is 59.5 liters at 121 kPa. what will be the volume if the pressure is reduced to 108 kPa, assuming temperature remains the same?

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  1. 10 February, 02:06
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    The volume of the gas V2 is 66.67 L

    Explanation:

    Given data

    V1 = 59.5 L

    V2=?

    T1 = 121K Pa

    T2 = 108 K Pa

    We have the formula,

    V1/T1 = V2/T2

    Rewrite the formula as,

    V2 = VI T1/T2

    V2 = 59.5 L * 121 K Pa/108 K Pa

    V2=7199.5 L K Pa / 108 K Pa

    V2=66.67 L

    The volume of the gas V2 is 66.67 L
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