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4 November, 12:56

Calculate the pH of a solution that has a [OH-] of 2.6 * 10^-6 M.

A. 8.4

B. 6.5

C. 7.7

D. 6.29

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Answers (1)
  1. 4 November, 14:54
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    A. 8.4

    Explanation:

    [OH⁻] = 2.6 * 10⁻⁶ Take the negative log of each side

    -log[OH⁻] = pOH = 5.59 Apply the pH/pOH relation

    pH + pOH = 14.00 Insert the value of pOH

    pH + 5.59 = 14.00 Subtract 5.59 from each side

    pH = 14.00 - 5.59 = 8.41
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