If 3 mole of gas at 0 °C has a pressure of 6 atm what is the volume of the gas? R = 0.0821 L*atm/mol*K.

The volume of the gas is 11, 2 L.

Explanation:

We use the ideal gas formula. We first convert the unit of temperature in degrees Celsius to Kelvin. We use the ideal gas constant R = 0.082 l atm / K mol. We solve v (volume):

273K = 0°C

PV=nRT - --> V = (nRT) / P

V = (3 mol x 0.082 l atm / K mol x 273 K) / 6 atm

V = 11, 193 L