X litres of carbon monoxide is present at STP. It is completely oxidized to CO2. The volume of CO2 formed is 11.207L at STP. What is the value of X in litres?

11.207 L

Explanation:

In first place, we need to state the reaction:

2CO (g) + O₂ (g) → 2CO₂ (g)

Ratio is 2:2, so 2 moles of CO can produce 2 moles of CO₂

At STP conditions, 1 mol of any gas occupy 22.4 L. Therefore if our volume is 11.207 L we are having 0.500 moles of gas. Let's verify with the Ideal Gases Law:

1 atm. 11.207 L = n. 0.082. 273.15K

1 atm. 11.207 L / 0.082. 273.15K = 0.500 moles.

As ratio is 2:2, 0.500 moles of CO₂ came from 0.500 moles of CO

So the volume in STP, must be the same!